Problema Solution
The area of a rectangle is 45ft^2 and the length of the rectangle is 1ft more than twice the width. Find the dimensions of the rectangle.
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
the length of the rectangle is 1ft more than twice the width
l = w + 1
the area of a rectangle is 45ft^2
w*l = 45
lets plug l = w + 1 in the above equation
w(w + 1) = 45
by solving the quadratic equation we find
w = 6.23 ft
l = 7.23 ft
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the dimensions of the rectangle are 7.23 ft length and 6.23 ft width.