Problema Solution
The points P(-6,-3), Q(-2,4), R(2,10)are on a coordinate plane. Where would S be located so that PQRS is a parrallogram?
Answer provided by our tutors
Parallelograms have to pairs of parallel sides. It is important to recognize that parallel lines have matching slopes. To calculate a slope, m, you find the "rise over run." In other words, you calculate the change in the y-coordinate, and divide that by the change in the x-coordinate between two points.
Step 1: Determine the slope between pairs of the given points, PQ and QR.
For PQ, slope = (4-(-3))/(-2-(-6))=7/4
For QR, slope = (10-4)/(2-(-2))=6/4=3/2
Step 2: Identify the requirements of Point S
In order to form a parallelogram, we need the following:
slope of RS = slope of PQ = 7/4
slope of PS = slope of QR = 3/2
Step 3: Let x denote the x-coordinate of point S, and y denote the y-coordinate of point S. This allows us to set up a system of equations using the slope requirements.
7/4 = (10-y)/(2-x)
3/2 = (-3-y)/(-6-x)
Step 4: Solve the system of equations. Start by solving each equation for y:
y=6.5 + 1.75x
y=6 + 1.5 x
Solve by graphing, addition, or substitution to find the solution x = -2, y = 3.
Therefore, Point S is located at (-2, 3).
You can graph this point with the others to see that they do, indeed, form a parallelogram.