
Marcus invested s sum of money at 5%. He invested an amount of money $250 more than the first amount at 6%. If the annual income from both investments totaled $59, how much did he invest at each rate. Use table and the 5step method to solve this problem.
Let x represent the first amount invested at 5%
Therefore, (x+ $250) would be the amount invested at 6%
question States***
.05x + .06(x + $250) = $59
solving for x
.05x + .06x + .06*$250 = %59
.11x = $59  .06*$250
.11x = $59  $15
.11x = $44
x = $44/.11 = $400, amount invested at 5%
the amount invested at 6% would be $650 ($400+ $250)
IV. CHECKING Our Answer***
.05*$400 + .06*$650 = $20 + $39 = $59
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