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The Problem

find two integers whose product is 299 such that one of the integers is three less than twice the other integer

Answer provided by our tutors

Q. let one of the two integers be x and other be y.

      according to question

                    y = 2x-3

give that xy =299

           => x(2x-3) =299

           => 2x^2 - 3x -299 =0

           => x =13 or -11.5

       since x is an integer x cant be -11.5 hence x =13 and y =23


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midight of March 05th