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find two integers whose product is 299 such that one of the integers is three less than twice the other integer

Q. let one of the two integers be x and other be y.

according to question

y = 2x-3

give that xy =299

=> x(2x-3) =299

=> 2x^2 - 3x -299 =0

=> x =13 or -11.5

since x is an integer x cant be -11.5 hence x =13 and y =23

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